Chapter 13 Pythagorean (P) Scale
13.1 The Form of the P Scale
The P scale is an inverted scale reading from right to left, hence the graduations are in red. The P scale is related to the D scale such that for a number "x" on the D scale, immediately below it on the P scale we have . This of course is only valid for (i.e. ), as we cannot have the square root of a negative number.
13.2 Calculating (P and D scales)
(Note we must have i.e. for to have a real value.)
Example 1:
Example 2:
Note: If then , thus to find we could either find x on the D scale and read off the P scale, or find x on the P scale and read off the D scale.
Exercise 13(a)
13.3 Converting Sines to Cosines (and vise versa)
From the relationship we can express:
Thus, given the value of sin θ we can read off directly the value of cos θ, and vise versa.
Example: sin 60° = 0.866 then cos 60° = 0.5
Exercise 13(b)
13.4 Sines of large angels and Cosines of small angels
For sines of large angles (i.e. in the region 80 to 90) working from the S scale is very inaccurate, as you can see from a glance at this region S scale.
Take for example sin 84°, the best we could estimate using the S and D scales would be 0.994. It would be impossible to make any more accurate estimation if the questing was 84°20. A better method is as follows:
Example: sin 84°6 = 0.9947
The same situation arises for cosines of small angels. Therefore, using the fact cos 5°54 = sin 84°6 we have:
Example: sin 5°54 = 0.9947
Note:
Exercise 13(c)
13.5 Square Roots (numbers just less than 1, 100, etc.)
The square root of numbers a little less than 1, 100, etc, can be obtained using the D and P scales to a greater degree of accuracy than in the conventional way, with the D (or C) and A (or B) scales.
Example 1: (Fig 13.4)
Express
Note: We must have the form to use the P scale. Thus we subtract 0.911 from 1 to obtain 0.089, and express 0.081 = (0.298)2 using the A and D scales.
Once we subtract 0.911 from 1, to obtain 0.089 the procedure is as follows:
Example 2:
Express
Note: For we would express it as:
and obtain as in example 2
i.e. = 10x0.9877
therefore = 9.877
Exercise 13(d)
13.6 The Difference of Two Squares (or )
This is the form often encountered when using Pythagoras Theorem to find the third side of a right triangle. We note that:
Thus, if we calculate using the C and D scales and transfer the result onto the P scale, on the D scale we have . Then we could easily multiply by x to obtain (i.e. .
This answer would be read off the D scale, thus to obtain we would read the answer off the A scale.
Example:
Express
(evaluate in any of the usual ways.)
Note: If instead of we required on the A scale as the answer.
Exercise 13(e)
13.7 Further Application of the P scale
Example |
Set the H.L. over |
Under the H.L. answer |
x on P scale |
on A scale |
|
x P |
BI |
|
x P |
K |
|
x P |
D (or CI) |
|
x A |
P |
|
x BI |
P |
|
x CI |
P |
|
x K |
P |
Example |
Set HL Over |
Under HL Place |
Reset HL over |
Under HL answer |
Index of D scale |
a on C scale |
x on P scale |
on C scale |
|
Index DI |
a CI |
x P |
CI |
|
x P |
a C |
Index C |
D |
Exercise 13(f)